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Início›📐 Matemática e Ciência›Calculadora de Raiz
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Calculadora de Raiz Online Grátis

Calculate nth root of any number with Newton's method steps and verification

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The Root Calculator finds the nth root of any positive number using Newton's method, showing successive approximation steps. It handles square roots, cube roots, and any higher-order root with verification at each iteration. Students checking their algebraic work, engineers computing signal amplitudes, and anyone needing precise root values beyond a simple square root will find it useful.

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Root Calculator

Calculate nth root of any number with Newton's method steps and verification

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Frequently Asked Questions

Our calculators use industry-standard formulas verified against academic sources and professional tools. Results are for informational and educational purposes — always verify important financial, health, or technical decisions with a qualified professional.
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Sobre Esta Calculadora

The nth root of a number x is the value y such that yⁿ = x. Square roots (n=2) and cube roots (n=3) are the most common, but higher-order roots appear in geometry, signal processing, and statistics. The nth root of x is equivalent to x^(1/n) in exponential notation, linking roots and exponents as inverse operations.

Newton's method (also called the Newton-Raphson method) provides a fast iterative algorithm for computing roots numerically. Starting from an initial estimate, it refines the guess using the formula y_new = ((n−1)×y + x/y^(n−1)) / n. For most starting values, this converges in fewer than 10 iterations to full precision.

Root calculations appear in solving quadratic equations (square root in the quadratic formula), geometry (diagonal of a square, side of a cube given volume), statistics (standard deviation involves a square root), and physics (root-mean-square values in AC circuits).

Cálculo linear.

Exemplo Resolvido

Finding the cube root of 216 using Newton's method

Entradas:

  • Number (x): 216
  • Root degree (n): 3

Passo a Passo:

  1. Find ∛216, i.e., the number y such that y³ = 216
  2. Newton's iteration: y_new = ((n−1)×y_old + x/y_old^(n−1)) / n
  3. Initial guess: y₀ = 6 (estimate)
  4. Iteration 1: y₁ = ((2×6) + 216/36) / 3 = (12 + 6) / 3 = 6.0
  5. Converged immediately: y = 6
  6. Verification: 6³ = 6 × 6 × 6 = 216 ✓
Resultado: ∛216 = 6 exactly. (216 = 6³ is a perfect cube.)

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Common Roots
√4 = 2Square root of 4
∛27 = 3Cube root of 27
√2 ≈ 1.4142Square root of 2
∜16 = 24th root of 16
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