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Início›📐 Matemática e Ciência›Combinatória / Probabilidade
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Combinatória / Probabilidade — Calculadora Online Grátis

nPr and nCr calculations with factorial steps and formula explanation

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The Permutation & Combination Calculator computes P(n,r) and C(n,r) simultaneously, showing the factorial expansion at each step. Permutations count ordered arrangements; combinations count unordered selections. Probability students, exam takers, and game designers use this tool to count possibilities without manually computing large factorials.

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Permutation & Combination

nPr and nCr calculations with factorial steps and formula explanation

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Frequently Asked Questions

Our calculators use industry-standard formulas verified against academic sources and professional tools. Results are for informational and educational purposes — always verify important financial, health, or technical decisions with a qualified professional.
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Sobre Esta Calculadora

Counting principles are the foundation of probability theory. Permutations (P(n,r) = n!/(n−r)!) count the number of ways to arrange r items from a set of n where order matters. Combinations (C(n,r) = n!/(r!×(n−r)!)) count the number of ways to choose r items where order does not matter. The distinction is critical: choosing a 3-member team from 8 people gives C(8,3) = 56 ways, but assigning them first, second, and third place gives P(8,3) = 336 ways.

This calculator shows the full factorial expansion, making it clear how the denominator cancels terms. For large n and small r, computing P or C directly via factorials can overflow — the calculator handles this gracefully.

Applications include probability problems (lottery odds, card game hands), combinatorics in algorithm analysis (Big-O notation), DNA sequence counting in bioinformatics, and scheduling problems in operations research.

Efetue sem dor a probabilidade das matrizes de combinações em loterias.

Fórmula

P(n,r) = n! / (n-r)!
C(n,r) = n! / (r! × (n-r)!)

Exemplo Resolvido

How many ways can you choose 3 items from 8 (ordered vs. unordered)?

Entradas:

  • n = 8 (total items)
  • r = 3 (items chosen)

Passo a Passo:

  1. Permutation P(8,3) — order matters:
  2. P(8,3) = 8! / (8−3)! = 8! / 5!
  3. = (8 × 7 × 6 × 5!) / 5! = 8 × 7 × 6 = 336
  4. Combination C(8,3) — order does not matter:
  5. C(8,3) = 8! / (3! × 5!) = 336 / 3! = 336 / 6 = 56
Resultado: P(8,3) = 336 ordered arrangements. C(8,3) = 56 unordered selections.

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